y^2+12y=620

Solution for y^2+12y=620 equation:

y^2+12y=620

We move all terms to the left:

y^2+12y-(620)=0

a = 1; b = 12; c = -620;
Δ = b2-4ac
Δ = 122-4·1·(-620)
Δ = 2624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2624}=\sqrt{64*41}=\sqrt{64}*\sqrt{41}=8\sqrt{41}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-8\sqrt{41}}{2*1}=\frac{-12-8\sqrt{41}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+8\sqrt{41}}{2*1}=\frac{-12+8\sqrt{41}}{2}
$